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Algebra / Linear inequalities in one or two variables Difficulty: Medium

A truck can haul a maximum weight of 5,630 pounds. During one trip, the truck will be used to haul a 190 -pound piece of equipment as well as several crates. Some of these crates weigh 25 pounds each and the others weigh 62 pounds each. Which inequality represents the possible combinations of the number of 25 -pound crates, x , and the number of 62 -pound crates, y , the truck can haul during one trip if only the piece of equipment and the crates are being hauled?

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Explanation

Choice A is correct. It's given that a truck can haul a maximum of 5,630 pounds. It's also given that during one trip, the truck will be used to haul a 190 -pound piece of equipment as well as several crates. It follows that the truck can haul at most 5,630-190, or 5,440 , pounds of crates. Since x represents the number of 25 -pound crates, the expression 25 x represents the weight of the 25 -pound crates. Since y represents the number of 62 -pound crates, 62 y represents the weight of the 62 -pound crates. Therefore, 25 x + 62 y represents the total weight of the crates the truck can haul. Since the truck can haul at most 5,440 pounds of crates, the total weight of the crates must be less than or equal to 5,440 pounds, or 25x+62y5,440.

Choice B is incorrect. This represents the possible combinations of the number of 25 -pound crates, x , and the number of 62 -pound crates, y , the truck can haul during one trip if it can haul a minimum, not a maximum, of 5,630 pounds.

Choice C is incorrect. This represents the possible combinations of the number of 62 -pound crates, x , and the number of 25 -pound crates, y , the truck can haul during one trip if only crates are being hauled.

Choice D is incorrect. This represents the possible combinations of the number of 62 -pound crates, x , and the number of 25 -pound crates, y , the truck can haul during one trip if it can haul a minimum, not a maximum, weight of 5,630 pounds and only crates are being hauled.